Linear Thermal Expansion

Calculate the change in length of a material due to temperature change.

°C
×10⁻⁶ /°C
Results

mm
m
Formula: ΔL = α × L₀ × ΔT

Area Thermal Expansion

Calculate the change in area of a material due to temperature change.

°C
×10⁻⁶ /°C
Results

mm²
Formula: ΔA ≈ 2α × A₀ × ΔT

Volumetric Thermal Expansion

Calculate the change in volume of a material or liquid due to temperature change.

°C
×10⁻⁶ /°C
Results

cm³
Formula: ΔV = β × V₀ × ΔT
(For solids, β ≈ 3α)

Material Database

Thermal expansion coefficients for common materials.

Solids
Material α (10⁻⁶/°C) β (10⁻⁶/°C)
Aluminum 23.1 69.3
Brass 19.0 57.0
Copper 17.0 51.0
Steel 12.0 36.0
Stainless Steel 10.4 31.2
Glass (ordinary) 9.0 27.0
Glass (Pyrex) 3.3 9.9
Concrete 12.0 36.0
Wood (pine) 5.0 15.0
Liquids
Material β (10⁻⁴/°C)
Water (20°C) 2.07
Ethanol 7.50
Glycerin 4.85
Mercury 1.82
Gasoline 9.50
Olive Oil 7.00

Thermal Expansion Formulas

Key equations for thermal expansion calculations.

Linear Thermal Expansion
ΔL = α × L₀ × ΔT

Where:

  • ΔL: Change in length
  • α: Coefficient of linear thermal expansion (per °C or per K)
  • L₀: Original length of the object
  • ΔT: Change in temperature (in °C or K)

This formula is used for rods, beams, wires, and other one-dimensional objects.

Area Thermal Expansion
ΔA ≈ 2α × A₀ × ΔT

Where:

  • ΔA: Change in area
  • α: Coefficient of linear thermal expansion
  • A₀: Original area
  • ΔT: Change in temperature

This approximation works well for small temperature changes and isotropic materials.

Volumetric Thermal Expansion
ΔV = β × V₀ × ΔT

Where:

  • ΔV: Change in volume
  • β: Coefficient of volumetric expansion (for solids, β ≈ 3α)
  • V₀: Original volume
  • ΔT: Change in temperature

For solids, the volumetric coefficient is approximately three times the linear coefficient. For liquids, β must be measured directly.

Example Calculations

Practical examples of thermal expansion calculations.

Example 1: Steel Rail Expansion

A steel railroad track is 10 meters long at 20°C. How much does it expand when the temperature reaches 40°C?

Given:

  • L₀ = 10 m
  • ΔT = 20°C (from 20°C to 40°C)
  • α (steel) = 12 × 10⁻⁶ /°C
ΔL = α × L₀ × ΔT
ΔL = (12 × 10⁻⁶) × 10 × 20
ΔL = 0.0024 m = 2.4 mm
Example 2: Glass Window Expansion

A glass window pane measures 1m × 1.5m at 10°C. What is its area at 30°C?

Given:

  • A₀ = 1.5 m²
  • ΔT = 20°C
  • α (glass) = 9 × 10⁻⁶ /°C
ΔA ≈ 2α × A₀ × ΔT
ΔA ≈ 2 × (9 × 10⁻⁶) × 1.5 × 20
ΔA ≈ 0.00054 m² = 5.4 cm²
Final area ≈ 1.50054 m²
Example 3: Aluminum Ball Expansion

An aluminum ball has a diameter of 10 cm at 25°C. What is its new volume at 75°C?

Given:

  • Diameter = 10 cm → V₀ = (4/3)π(5)³ ≈ 523.6 cm³
  • ΔT = 50°C
  • α (aluminum) = 23 × 10⁻⁶ /°C → β ≈ 69 × 10⁻⁶ /°C
ΔV = β × V₀ × ΔT
ΔV = (69 × 10⁻⁶) × 523.6 × 50
ΔV ≈ 1.806 cm³
Final volume ≈ 525.406 cm³
Example 4: Gasoline Expansion

A car's gas tank holds 50 liters of gasoline at 15°C. How much gasoline will overflow if the temperature rises to 35°C?

Given:

  • V₀ = 50 L
  • ΔT = 20°C
  • β (gasoline) = 950 × 10⁻⁶ /°C
ΔV = β × V₀ × ΔT
ΔV = (950 × 10⁻⁶) × 50 × 20
ΔV = 0.95 L
Final volume ≈ 50.95 L