Boiler Efficiency Calculator
Instantly calculate the thermal efficiency of your boiler system using direct or indirect method—ideal for energy audits and mechanical analysis.
Direct Method Calculation
Boiler Efficiency (Direct Method)
0.00%
Efficiency = (Output Energy / Input Energy) × 100
Indirect Method Calculation
Boiler Efficiency (Indirect Method)
0.00%
Efficiency = 100% - Total Losses
Loss Breakdown:
Dry Flue Gas Loss:
0%
Moisture Loss:
0%
Unburnt Carbon Loss:
0%
Radiation & Convection Loss:
0%
Miscellaneous Loss:
0%
How To Use This Calculator
Step-by-Step Instructions
- Select the calculation method (Direct or Indirect) from the left sidebar.
- Enter required data:
- Direct Method: Fuel consumption, calorific value, steam output, and enthalpy values.
- Indirect Method: Various heat loss parameters from your boiler system.
- The calculator will display results in real-time as you enter values.
- Optionally, you can:
- View the loss breakdown chart (for Indirect Method)
- Copy results to clipboard
- Load example values for demonstration
Sample Calculation (Direct Method)
| Parameter | Value |
|---|---|
| Fuel Used | 100 kg/hr |
| Calorific Value | 42000 kJ/kg |
| Steam Output | 1200 kg/hr |
| Enthalpy of Steam | 2760 kJ/kg |
| Feedwater Enthalpy | 420 kJ/kg |
| Result | ~67.7% Boiler Efficiency |
Tips & Best Practices
- Typical boiler efficiency ranges from 70% to 90% for modern systems.
- For accurate results, use measured values rather than design specifications.
- The indirect method helps identify which losses are most significant for potential improvements.
- Regular efficiency calculations can help track boiler performance over time.
Reference Data
Fuel Calorific Values
| Fuel Type | Calorific Value (kJ/kg) | Calorific Value (kcal/kg) | Calorific Value (BTU/lb) |
|---|---|---|---|
| Coal (Bituminous) | 30,000 – 35,000 | 7,170 – 8,360 | 12,900 – 15,000 |
| Furnace Oil | 41,000 – 45,000 | 9,800 – 10,750 | 17,600 – 19,300 |
| Natural Gas | 48,000 – 52,000 | 11,470 – 12,420 | 20,600 – 22,300 |
| Biomass Pellets | 14,000 – 18,000 | 3,350 – 4,300 | 6,000 – 7,700 |
| Diesel | 45,000 – 46,500 | 10,750 – 11,100 | 19,300 – 20,000 |
Typical Steam Enthalpy Values
| Pressure (bar) | Saturation Temperature (°C) | Feedwater Enthalpy (hf, kJ/kg) | Steam Enthalpy (hg, kJ/kg) |
|---|---|---|---|
| 1 | 99.6 | 417 | 2,675 |
| 5 | 151.8 | 640 | 2,748 |
| 10 | 179.9 | 762 | 2,778 |
| 15 | 198.3 | 844 | 2,792 |
| 20 | 212.4 | 908 | 2,799 |
Formulas
Direct Method:
Efficiency(%) = (Output Energy / Input Energy) × 100
Input Energy = Fuel Consumed × Calorific Value
Output Energy = Steam Output × (Enthalpy of Steam - Feedwater Enthalpy)
Indirect Method:
Efficiency(%) = 100 - Total Heat Losses
Typical losses include:
- Dry flue gas loss
- Moisture in fuel loss
- Hydrogen in fuel loss
- Radiation & convection losses
- Unburnt carbon loss
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